Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
For example, two is written as II
in Roman numeral, just two one’s added together. Twelve is written as, XII
, which is simply X
+ II
. The number twenty seven is written as XXVII
, which is XX
+ V
+ II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed beforeV
(5) andX
(10) to make 4 and 9.X
can be placed beforeL
(50) andC
(100) to make 40 and 90.C
can be placed beforeD
(500) andM
(1000) to make 400 and 900.
Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.
罗马数字包含以下七种字符:I
, V
, X
, L
,C
,D
和 M
。
1 2 3 4 5 6 7 8 |
<strong>字符</strong> <strong>数值</strong> I 1 V 5 X 10 L 50 C 100 D 500 M 1000 |
例如, 罗马数字 2 写做 II
,即为两个并列的 1。12 写做 XII
,即为 X
+ II
。 27 写做 XXVII
, 即为 XX
+ V
+ II
。
通常情况下,罗马数字中小的数字在大的数字的右边。但也存在特例,例如 4 不写做 IIII
,而是 IV
。数字 1 在数字 5 的左边,所表示的数等于大数 5 减小数 1 得到的数值 4 。同样地,数字 9 表示为 IX
。这个特殊的规则只适用于以下六种情况:
I
可以放在V
(5) 和X
(10) 的左边,来表示 4 和 9。X
可以放在L
(50) 和C
(100) 的左边,来表示 40 和 90。C
可以放在D
(500) 和M
(1000) 的左边,来表示 400 和 900。
给定一个罗马数字,将其转换成整数。输入确保在 1 到 3999 的范围内。
示例 1:
1 2 |
<strong>输入:</strong> "III" <strong>输出:</strong> 3 |
示例 2:
1 2 |
<strong>输入:</strong> "IV" <strong>输出:</strong> 4 |
示例 3:
1 2 |
<strong>输入:</strong> "IX" <strong>输出:</strong> 9 |
示例 4:
1 2 3 |
<strong>输入:</strong> "LVIII" <strong>输出:</strong> 58 <strong>解释:</strong> L = 50, V = 5, III = 3. |
示例 5:
1 2 3 |
<strong>输入:</strong> "MCMXCIV" <strong>输出:</strong> 1994 <strong>解释:</strong> M = 1000, CM = 900, XC = 90, IV = 4. |
解答
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dict = { 'I':1, 'V':5, 'X':10, 'L':50, 'C':100, 'D':500, 'M':1000 } roman_list = list(s) sum = 0 for i in range(len(roman_list)-1): if dict[roman_list[i]] < dict[roman_list[i+1]]: sum -= dict[roman_list[i]] else: sum += dict[roman_list[i]] sum = sum + dict[roman_list[-1]] return sum |
输出
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Solution().romanToInt('LVIII') 58 |
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Solution().romanToInt('MCMXCIV') 1994 |